Различия
Показаны различия между двумя версиями страницы.
| Следующая версия | Предыдущая версия | ||
| optics:res4.5 [2020/05/14 11:27] – создано root | optics:res4.5 [2020/05/14 11:31] (текущий) – root | ||
|---|---|---|---|
| Строка 5: | Строка 5: | ||
| Магнитное поле: | Магнитное поле: | ||
| - | $$B_{\alpha}=\left(\frac{\omega}{c}+\frac{i}{r}\right)\frac{\omega}{cr}p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\sin\theta\approx$$\pause | + | $$B_{\alpha}=\left(\frac{\omega}{c}-\frac{i}{r}\right)\frac{\omega}{cr}p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\sin\theta\approx$$ |
| $$ | $$ | ||
| - | \frac{i\omega}{cr^{2}}p_{0}e^{i\omega t}\sin\theta\pause=\frac{1}{cr^{2}}\frac{\partial}{\partial t}p_{0}e^{i\omega t}\sin\theta\pause=\frac{1}{cr^{2}}\frac{\partial}{\partial t}q\ell_{0}e^{i\omega t}\sin\theta\pause=$$ | + | -\frac{i\omega}{cr^{2}}p_{0}e^{i\omega t}\sin\theta=-\frac{1}{cr^{2}}\frac{\partial}{\partial t}p_{0}e^{i\omega t}\sin\theta=-\frac{1}{cr^{2}}\frac{\partial}{\partial t}q\ell_{0}e^{i\omega t}\sin\theta=$$ |
| - | $$\frac{J}{cr^{2}}\ell_{0}\sin\theta\pause=\frac{J\left[\vec{r}\times\vec{\ell}_{0}\right]}{cr^{3}}.$$ | + | $$-\frac{J}{cr^{2}}\ell_{0}\sin\theta=-\frac{J\left[\vec{r}\times\vec{\ell}_{0}\right]}{cr^{3}}.$$ |
| Электрическое поле | Электрическое поле | ||
| - | \pause | + | |
| - | $$E_{r}=2\left(\frac{1}{r}-\frac{i\omega}{c}\right)\frac{p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\cos\theta}{r^{2}}\approx$$\pause | + | $$E_{r}=-2\left(\frac{1}{r}+\frac{i\omega}{c}\right)\frac{p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\cos\theta}{r^{2}}\approx$$ |
| $$ | $$ | ||
| - | 2\frac{p_{0}e^{i\omega t}\cos\theta}{r^{3}}\pause=2\frac{p\cos\theta}{r^{3}}, | + | -2\frac{p_{0}e^{i\omega t}\cos\theta}{r^{3}}=-2\frac{p\cos\theta}{r^{3}}, |
| - | \pause | + | |
| - | $$E_{\theta}=\left(\frac{1}{r^{2}}+\frac{\omega^{2}}{c^{2}}+\frac{i\omega}{rc}\right)\frac{p_{0}\sin\theta e^{i\omega\left(t-\frac{r}{c}\right)}}{r}\approx$$\pause | + | $$E_{\theta}=\left(\frac{1}{r^{2}}+\frac{\omega^{2}}{c^{2}}-\frac{i\omega}{rc}\right)\frac{p_{0}\sin\theta e^{i\omega\left(t-\frac{r}{c}\right)}}{r}\approx$$ |
| $$ | $$ | ||
| - | \frac{p_{0}\sin\theta e^{i\omega t}}{r^{3}}\pause=\frac{p\sin\theta}{r^{3}}.$$ | + | \frac{p_{0}\sin\theta e^{i\omega t}}{r^{3}}=\frac{p\sin\theta}{r^{3}}.$$ |