Различия

Показаны различия между двумя версиями страницы.

--- optics:res4.5 [2020/05/14 11:28] – root
+++ optics:res4.5 [2020/05/14 11:31] (текущий) – root
@@ Строка 5: / Строка 5: @@
 Магнитное поле:
-$$B_{\alpha}=\left(\frac{\omega}{c}+\frac{i}{r}\right)\frac{\omega}{cr}p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\sin\theta\approx$$
+$$B_{\alpha}=\left(\frac{\omega}{c}-\frac{i}{r}\right)\frac{\omega}{cr}p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\sin\theta\approx$$
 $$
-\frac{i\omega}{cr^{2}}p_{0}e^{i\omega t}\sin\theta=\frac{1}{cr^{2}}\frac{\partial}{\partial t}p_{0}e^{i\omega t}\sin\theta=\frac{1}{cr^{2}}\frac{\partial}{\partial t}q\ell_{0}e^{i\omega t}\sin\theta=$$
+-\frac{i\omega}{cr^{2}}p_{0}e^{i\omega t}\sin\theta=-\frac{1}{cr^{2}}\frac{\partial}{\partial t}p_{0}e^{i\omega t}\sin\theta=-\frac{1}{cr^{2}}\frac{\partial}{\partial t}q\ell_{0}e^{i\omega t}\sin\theta=$$
-$$\frac{J}{cr^{2}}\ell_{0}\sin\theta=\frac{J\left[\vec{r}\times\vec{\ell}_{0}\right]}{cr^{3}}.$$
+$$-\frac{J}{cr^{2}}\ell_{0}\sin\theta=-\frac{J\left[\vec{r}\times\vec{\ell}_{0}\right]}{cr^{3}}.$$
 Электрическое поле
-$$E_{r}=2\left(\frac{1}{r}-\frac{i\omega}{c}\right)\frac{p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\cos\theta}{r^{2}}\approx$$
+$$E_{r}=-2\left(\frac{1}{r}+\frac{i\omega}{c}\right)\frac{p_{0}e^{i\omega\left(t-\frac{r}{c}\right)}\cos\theta}{r^{2}}\approx$$
 $$
-\frac{p_{0}e^{i\omega t}\cos\theta}{r^{3}}=2\frac{p\cos\theta}{r^{3}},$$
+-2\frac{p_{0}e^{i\omega t}\cos\theta}{r^{3}}=-2\frac{p\cos\theta}{r^{3}},$$
-$$E_{\theta}=\left(\frac{1}{r^{2}}+\frac{\omega^{2}}{c^{2}}+\frac{i\omega}{rc}\right)\frac{p_{0}\sin\theta e^{i\omega\left(t-\frac{r}{c}\right)}}{r}\approx$$
+$$E_{\theta}=\left(\frac{1}{r^{2}}+\frac{\omega^{2}}{c^{2}}-\frac{i\omega}{rc}\right)\frac{p_{0}\sin\theta e^{i\omega\left(t-\frac{r}{c}\right)}}{r}\approx$$
 $$
 \frac{p_{0}\sin\theta e^{i\omega t}}{r^{3}}=\frac{p\sin\theta}{r^{3}}.$$